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x^2-102x+1080=0
a = 1; b = -102; c = +1080;
Δ = b2-4ac
Δ = -1022-4·1·1080
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-78}{2*1}=\frac{24}{2} =12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+78}{2*1}=\frac{180}{2} =90 $
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